A=5x-3+5x(2x+4)

Solution for A=5x-3+5x(2x+4) equation:

=5A-3+5A(2A+4)

We move all terms to the left:

-(5A-3+5A(2A+4))=0


We calculate terms in parentheses: -(5A-3+5A(2A+4)), so:

5A-3+5A(2A+4)

determiningTheFunctionDomain
5A+5A(2A+4)-3

We multiply parentheses

10A^2+5A+20A-3

We add all the numbers together, and all the variables

10A^2+25A-3

Back to the equation:

-(10A^2+25A-3)


We get rid of parentheses

-10A^2-25A+3=0

a = -10; b = -25; c = +3;
Δ = b2-4ac
Δ = -252-4·(-10)·3
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{745}}{2*-10}=\frac{25-\sqrt{745}}{-20}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{745}}{2*-10}=\frac{25+\sqrt{745}}{-20}
$