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=5A+4/5A
We move all terms to the left:
-(5A+4/5A)=0
Domain of the equation: 5A)!=0We add all the numbers together, and all the variables
A!=0/1
A!=0
A∈R
-(+5A+4/5A)=0
We get rid of parentheses
-5A-4/5A=0
We multiply all the terms by the denominator
-5A*5A-4=0
Wy multiply elements
-25A^2-4=0
a = -25; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-25)·(-4)
Δ = -400
Delta is less than zero, so there is no solution for the equation
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