A=6x(3x+2)

Solution for A=6x(3x+2) equation:

=6A(3A+2)

We move all terms to the left:

-(6A(3A+2))=0


We calculate terms in parentheses: -(6A(3A+2)), so:

6A(3A+2)

We multiply parentheses

18A^2+12A

Back to the equation:

-(18A^2+12A)


We get rid of parentheses

-18A^2-12A=0

a = -18; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-18)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-18}=\frac{0}{-36}
=0
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-18}=\frac{24}{-36}
=-2/3
$