A=7(x+4)-(2x-3)(2x+3)

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Solution for A=7(x+4)-(2x-3)(2x+3) equation: 



=7(A+4)-(2A-3)(2A+3)

We move all terms to the left:

-(7(A+4)-(2A-3)(2A+3))=0

We use the square of the difference formula

4A^2+9=0

a = 4; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·4·9
Δ = -144
Delta is less than zero, so there is no solution for the equation

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