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=7(A-4)+(6A-5)(-3A+4)
We move all terms to the left:
-(7(A-4)+(6A-5)(-3A+4))=0
We multiply parentheses ..
-(7(A-4)+(-18A^2+24A+15A-20))=0
We calculate terms in parentheses: -(7(A-4)+(-18A^2+24A+15A-20)), so:We get rid of parentheses
7(A-4)+(-18A^2+24A+15A-20)
determiningTheFunctionDomain (-18A^2+24A+15A-20)+7(A-4)
We multiply parentheses
(-18A^2+24A+15A-20)+7A-28
We get rid of parentheses
-18A^2+24A+15A+7A-20-28
We add all the numbers together, and all the variables
-18A^2+46A-48
Back to the equation:
-(-18A^2+46A-48)
18A^2-46A+48=0
a = 18; b = -46; c = +48;
Δ = b2-4ac
Δ = -462-4·18·48
Δ = -1340
Delta is less than zero, so there is no solution for the equation
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