A=9/5(h-57)

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Solution for A=9/5(h-57) equation: 



=9/5(A-57)

We move all terms to the left:

-(9/5(A-57))=0



Domain of the equation: 5(A-57))!=0

A∈R



We multiply all the terms by the denominator


-(9=0

We add all the numbers together, and all the variables

=0

A=0/1

A=0

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