A=Bh/3

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Solution for A=Bh/3 equation:


((2*z-3)^2)/5 = ((3*z)^1)/5

a^1*((35*a^2*b^2)/7)*b^6 = 0

((2*y-3)^2)/3 = ((3*y)^1)/3

12354;454464

((2*y-3)^2)/3 = (3*y)^(1^3)

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