A=P(1+.04/52)52t

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Solution for A=P(1+.04/52)52t equation: 



=(1+.04/52)52A

We move all terms to the left:

-((1+.04/52)52A)=0



Domain of the equation: 52)52A)!=0

A!=0/1

A!=0

A∈R



We add all the numbers together, and all the variables

-((.04/52+1)52A)=0

We multiply all the terms by the denominator


-((.04=0

We add all the numbers together, and all the variables

=0

A=0/1

A=0

Równanie nie ma rozwiązania

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