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=A(150-2A)
We move all terms to the left:
-(A(150-2A))=0
We add all the numbers together, and all the variables
-(A(-2A+150))=0
We calculate terms in parentheses: -(A(-2A+150)), so:We get rid of parentheses
A(-2A+150)
We multiply parentheses
-2A^2+150A
Back to the equation:
-(-2A^2+150A)
2A^2-150A=0
a = 2; b = -150; c = 0;
Δ = b2-4ac
Δ = -1502-4·2·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-150}{2*2}=\frac{0}{4} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+150}{2*2}=\frac{300}{4} =75 $
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