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=A(500-2A)
We move all terms to the left:
-(A(500-2A))=0
We add all the numbers together, and all the variables
-(A(-2A+500))=0
We calculate terms in parentheses: -(A(-2A+500)), so:We get rid of parentheses
A(-2A+500)
We multiply parentheses
-2A^2+500A
Back to the equation:
-(-2A^2+500A)
2A^2-500A=0
a = 2; b = -500; c = 0;
Δ = b2-4ac
Δ = -5002-4·2·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{250000}=500$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-500}{2*2}=\frac{0}{4} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+500}{2*2}=\frac{1000}{4} =250 $
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