A=x(500-3x)

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Solution for A=x(500-3x) equation:



=A(500-3A)
We move all terms to the left:
-(A(500-3A))=0
We add all the numbers together, and all the variables
-(A(-3A+500))=0
We calculate terms in parentheses: -(A(-3A+500)), so:
A(-3A+500)
We multiply parentheses
-3A^2+500A
Back to the equation:
-(-3A^2+500A)
We get rid of parentheses
3A^2-500A=0
a = 3; b = -500; c = 0;
Δ = b2-4ac
Δ = -5002-4·3·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-500}{2*3}=\frac{0}{6} =0 $
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+500}{2*3}=\frac{1000}{6} =166+2/3 $

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