Ax2B-2A=168

Solution for Ax2B-2A=168 equation:

A2-2=168

We move all terms to the left:

A2-2-(168)=0

We add all the numbers together, and all the variables

A^2-170=0

a = 1; b = 0; c = -170;
Δ = b2-4ac
Δ = 02-4·1·(-170)
Δ = 680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{680}=\sqrt{4*170}=\sqrt{4}*\sqrt{170}=2\sqrt{170}$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{170}}{2*1}=\frac{0-2\sqrt{170}}{2}
=-\frac{2\sqrt{170}}{2}
=-\sqrt{170}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{170}}{2*1}=\frac{0+2\sqrt{170}}{2}
=\frac{2\sqrt{170}}{2}
=\sqrt{170}
$