B(5px-3c)=A(q-4)

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Solution for B(5px-3c)=A(q-4) equation:


Simplifying
B(5px + -3c) = A(q + -4)

Reorder the terms:
B(-3c + 5px) = A(q + -4)
(-3c * B + 5px * B) = A(q + -4)
(-3cB + 5pxB) = A(q + -4)

Reorder the terms:
-3cB + 5pxB = A(-4 + q)
-3cB + 5pxB = (-4 * A + q * A)
-3cB + 5pxB = (-4A + qA)

Solving
-3cB + 5pxB = -4A + qA

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5pxB' to each side of the equation.
-3cB + 5pxB + -5pxB = -4A + -5pxB + qA

Combine like terms: 5pxB + -5pxB = 0
-3cB + 0 = -4A + -5pxB + qA
-3cB = -4A + -5pxB + qA

Divide each side by '-3B'.
c = 1.333333333AB-1 + 1.666666667px + -0.3333333333qAB-1

Simplifying
c = 1.333333333AB-1 + 1.666666667px + -0.3333333333qAB-1

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