B(5px-3c)=a(qx-4)forx

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Solution for B(5px-3c)=a(qx-4)forx equation: 


Simplifying
B(5px + -3c) = a(qx + -4) * forx

Reorder the terms:
B(-3c + 5px) = a(qx + -4) * forx
(-3c * B + 5px * B) = a(qx + -4) * forx
(-3cB + 5pxB) = a(qx + -4) * forx

Reorder the terms:
-3cB + 5pxB = a(-4 + qx) * forx

Reorder the terms for easier multiplication:
-3cB + 5pxB = a * forx(-4 + qx)

Multiply a * forx
-3cB + 5pxB = aforx(-4 + qx)
-3cB + 5pxB = (-4 * aforx + qx * aforx)

Reorder the terms:
-3cB + 5pxB = (afoqrx2 + -4aforx)
-3cB + 5pxB = (afoqrx2 + -4aforx)

Solving
-3cB + 5pxB = afoqrx2 + -4aforx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5pxB' to each side of the equation.
-3cB + 5pxB + -5pxB = afoqrx2 + -4aforx + -5pxB

Combine like terms: 5pxB + -5pxB = 0
-3cB + 0 = afoqrx2 + -4aforx + -5pxB
-3cB = afoqrx2 + -4aforx + -5pxB

Divide each side by '-3B'.
c = -0.3333333333afoqrx2B-1 + 1.333333333aforxB-1 + 1.666666667px

Simplifying
c = -0.3333333333afoqrx2B-1 + 1.333333333aforxB-1 + 1.666666667px

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