B(h)=100-0.12h

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Solution for B(h)=100-0.12h equation: 



(B)=100-0.12B

We move all terms to the left:

(B)-(100-0.12B)=0

We add all the numbers together, and all the variables

B-(-0.12B+100)=0

We get rid of parentheses

B+0.12B-100=0

We add all the numbers together, and all the variables

1.12B-100=0

We move all terms containing B to the left, all other terms to the right

1.12B=100

B=100/1.12

B=89+0.31999999999999/1.12

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