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(B)=0.1B^2+3B+50
We move all terms to the left:
(B)-(0.1B^2+3B+50)=0
We get rid of parentheses
-0.1B^2+B-3B-50=0
We add all the numbers together, and all the variables
-0.1B^2-2B-50=0
a = -0.1; b = -2; c = -50;
Δ = b2-4ac
Δ = -22-4·(-0.1)·(-50)
Δ = -16
Delta is less than zero, so there is no solution for the equation
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