B(x+3y+7z)=119

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Solution for B(x+3y+7z)=119 equation: 


Simplifying
B(x + 3y + 7z) = 119
(x * B + 3y * B + 7z * B) = 119
(xB + 3yB + 7zB) = 119

Solving
xB + 3yB + 7zB = 119

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3yB' to each side of the equation.
xB + 3yB + -3yB + 7zB = 119 + -3yB

Combine like terms: 3yB + -3yB = 0
xB + 0 + 7zB = 119 + -3yB
xB + 7zB = 119 + -3yB

Add '-7zB' to each side of the equation.
xB + 7zB + -7zB = 119 + -3yB + -7zB

Combine like terms: 7zB + -7zB = 0
xB + 0 = 119 + -3yB + -7zB
xB = 119 + -3yB + -7zB

Divide each side by 'B'.
x = 119B-1 + -3y + -7z

Simplifying
x = 119B-1 + -3y + -7z

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