B(z+4)=5(13+z)

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Solution for B(z+4)=5(13+z) equation:


Simplifying
B(z + 4) = 5(13 + z)

Reorder the terms:
B(4 + z) = 5(13 + z)
(4 * B + z * B) = 5(13 + z)
(4B + zB) = 5(13 + z)
4B + zB = (13 * 5 + z * 5)
4B + zB = (65 + 5z)

Solving
4B + zB = 65 + 5z

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Reorder the terms:
-65 + 4B + -5z + zB = 65 + 5z + -65 + -5z

Reorder the terms:
-65 + 4B + -5z + zB = 65 + -65 + 5z + -5z

Combine like terms: 65 + -65 = 0
-65 + 4B + -5z + zB = 0 + 5z + -5z
-65 + 4B + -5z + zB = 5z + -5z

Combine like terms: 5z + -5z = 0
-65 + 4B + -5z + zB = 0

The solution to this equation could not be determined.

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