B)-3c-12=5+c

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Solution for B)-3c-12=5+c equation:



)-3B-12=5+B
We move all terms to the left:
)-3B-12-(5+B)=0
We add all the numbers together, and all the variables
-3B-(B+5)-12+)=0
We add all the numbers together, and all the variables
-3B-(B+5)=0
We get rid of parentheses
-3B-B-5=0
We add all the numbers together, and all the variables
-4B-5=0
We move all terms containing B to the left, all other terms to the right
-4B=5
B=5/-4
B=-1+1/4

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