B+(b+1)+(b+2)/4=21

Solution for B+(b+1)+(b+2)/4=21 equation:

+(B+1)+(B+2)/4=21

We move all terms to the left:

+(B+1)+(B+2)/4-(21)=0

We get rid of parentheses

B+(B+2)/4+1-21=0

We multiply all the terms by the denominator


B*4+(B+2)+1*4-21*4=0

We add all the numbers together, and all the variables

B*4+(B+2)-80=0

Wy multiply elements

4B+(B+2)-80=0

We get rid of parentheses

4B+B+2-80=0

We add all the numbers together, and all the variables

5B-78=0

We move all terms containing B to the left, all other terms to the right

5B=78

B=78/5

B=15+3/5