B+1.5(b+2)+15=(2b-9)+90

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Solution for B+1.5(b+2)+15=(2b-9)+90 equation: 



+1.5(B+2)+15=(2B-9)+90

We move all terms to the left:

+1.5(B+2)+15-((2B-9)+90)=0

We multiply parentheses

1.5B-((2B-9)+90)+3+15=0



We calculate terms in parentheses: -((2B-9)+90), so:

(2B-9)+90

We get rid of parentheses

2B-9+90

We add all the numbers together, and all the variables

2B+81

Back to the equation:

-(2B+81)



We add all the numbers together, and all the variables

1.5B-(2B+81)+18=0

We get rid of parentheses

1.5B-2B-81+18=0

We add all the numbers together, and all the variables

-0.5B-63=0

We move all terms containing B to the left, all other terms to the right

-0.5B=63

B=63/-0.5

B=-126

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