B+2(b+5)=(b-1)+13

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Solution for B+2(b+5)=(b-1)+13 equation: 


Simplifying
B + 2(b + 5) = (b + -1) + 13

Reorder the terms:
B + 2(5 + b) = (b + -1) + 13
B + (5 * 2 + b * 2) = (b + -1) + 13
B + (10 + 2b) = (b + -1) + 13

Reorder the terms:
10 + B + 2b = (b + -1) + 13

Reorder the terms:
10 + B + 2b = (-1 + b) + 13

Remove parenthesis around (-1 + b)
10 + B + 2b = -1 + b + 13

Reorder the terms:
10 + B + 2b = -1 + 13 + b

Combine like terms: -1 + 13 = 12
10 + B + 2b = 12 + b

Solving
10 + B + 2b = 12 + b

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + B + -10 + 2b = 12 + -10 + b

Reorder the terms:
10 + -10 + B + 2b = 12 + -10 + b

Combine like terms: 10 + -10 = 0
0 + B + 2b = 12 + -10 + b
B + 2b = 12 + -10 + b

Combine like terms: 12 + -10 = 2
B + 2b = 2 + b

Add '-2b' to each side of the equation.
B + 2b + -2b = 2 + b + -2b

Combine like terms: 2b + -2b = 0
B + 0 = 2 + b + -2b
B = 2 + b + -2b

Combine like terms: b + -2b = -1b
B = 2 + -1b

Simplifying
B = 2 + -1b

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