B+2(b+5)=3(b-1)+13

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Solution for B+2(b+5)=3(b-1)+13 equation: 


Simplifying
B + 2(b + 5) = 3(b + -1) + 13

Reorder the terms:
B + 2(5 + b) = 3(b + -1) + 13
B + (5 * 2 + b * 2) = 3(b + -1) + 13
B + (10 + 2b) = 3(b + -1) + 13

Reorder the terms:
10 + B + 2b = 3(b + -1) + 13

Reorder the terms:
10 + B + 2b = 3(-1 + b) + 13
10 + B + 2b = (-1 * 3 + b * 3) + 13
10 + B + 2b = (-3 + 3b) + 13

Reorder the terms:
10 + B + 2b = -3 + 13 + 3b

Combine like terms: -3 + 13 = 10
10 + B + 2b = 10 + 3b

Add '-10' to each side of the equation.
10 + B + -10 + 2b = 10 + -10 + 3b

Reorder the terms:
10 + -10 + B + 2b = 10 + -10 + 3b

Combine like terms: 10 + -10 = 0
0 + B + 2b = 10 + -10 + 3b
B + 2b = 10 + -10 + 3b

Combine like terms: 10 + -10 = 0
B + 2b = 0 + 3b
B + 2b = 3b

Solving
B + 2b = 3b

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-2b' to each side of the equation.
B + 2b + -2b = 3b + -2b

Combine like terms: 2b + -2b = 0
B + 0 = 3b + -2b
B = 3b + -2b

Combine like terms: 3b + -2b = 1b
B = 1b

Simplifying
B = 1b

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