B+2(b-3)=2(4b+3)+b

Solution for B+2(b-3)=2(4b+3)+b equation:

Simplifying
B + 2(b + -3) = 2(4b + 3) + b

Reorder the terms:
B + 2(-3 + b) = 2(4b + 3) + b
B + (-3 * 2 + b * 2) = 2(4b + 3) + b
B + (-6 + 2b) = 2(4b + 3) + b

Reorder the terms:
-6 + B + 2b = 2(4b + 3) + b

Reorder the terms:
-6 + B + 2b = 2(3 + 4b) + b
-6 + B + 2b = (3 * 2 + 4b * 2) + b
-6 + B + 2b = (6 + 8b) + b

Combine like terms: 8b + b = 9b
-6 + B + 2b = 6 + 9b

Solving
-6 + B + 2b = 6 + 9b

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + B + 6 + 2b = 6 + 6 + 9b

Reorder the terms:
-6 + 6 + B + 2b = 6 + 6 + 9b

Combine like terms: -6 + 6 = 0
0 + B + 2b = 6 + 6 + 9b
B + 2b = 6 + 6 + 9b

Combine like terms: 6 + 6 = 12
B + 2b = 12 + 9b

Add '-2b' to each side of the equation.
B + 2b + -2b = 12 + 9b + -2b

Combine like terms: 2b + -2b = 0
B + 0 = 12 + 9b + -2b
B = 12 + 9b + -2b

Combine like terms: 9b + -2b = 7b
B = 12 + 7b

Simplifying
B = 12 + 7b