B+2/b-6=b-1/b-7

Solution for B+2/b-6=b-1/b-7 equation:

+2/B-6=B-1/B-7

We move all terms to the left:

+2/B-6-(B-1/B-7)=0


Domain of the equation: B!=0

B∈R



Domain of the equation: B-7)!=0

B∈R


We get rid of parentheses

2/B-B+1/B+7-6=0

We multiply all the terms by the denominator


-B*B+7*B-6*B+2+1=0

We add all the numbers together, and all the variables

B-B*B+3=0

Wy multiply elements

-1B^2+B+3=0

a = -1; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-1)·3
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{13}}{2*-1}=\frac{-1-\sqrt{13}}{-2}
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{13}}{2*-1}=\frac{-1+\sqrt{13}}{-2}
$