B+2=5(a-3)

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Solution for B+2=5(a-3) equation: 



+2=5(B-3)

We move all terms to the left:

+2-(5(B-3))=0



We calculate terms in parentheses: -(5(B-3)), so:

5(B-3)

We multiply parentheses

5B-15

Back to the equation:

-(5B-15)



We get rid of parentheses

-5B+15+2=0

We add all the numbers together, and all the variables

-5B+17=0

We move all terms containing B to the left, all other terms to the right

-5B=-17

B=-17/-5

B=3+2/5

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