B+3(b-4)=84

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Solution for B+3(b-4)=84 equation: 



+3(B-4)=84

We move all terms to the left:

+3(B-4)-(84)=0

We multiply parentheses

3B-12-84=0

We add all the numbers together, and all the variables

3B-96=0

We move all terms containing B to the left, all other terms to the right

3B=96

B=96/3

B=32

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