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+3/2B+(B+45)+90+(2B+90)=540
We move all terms to the left:
+3/2B+(B+45)+90+(2B+90)-(540)=0
Domain of the equation: 2B!=0We add all the numbers together, and all the variables
B!=0/2
B!=0
B∈R
3/2B+(B+45)+(2B+90)-450=0
We get rid of parentheses
3/2B+B+2B+45+90-450=0
We multiply all the terms by the denominator
B*2B+2B*2B+45*2B+90*2B-450*2B+3=0
Wy multiply elements
2B^2+4B^2+90B+180B-900B+3=0
We add all the numbers together, and all the variables
6B^2-630B+3=0
a = 6; b = -630; c = +3;
Δ = b2-4ac
Δ = -6302-4·6·3
Δ = 396828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{396828}=\sqrt{36*11023}=\sqrt{36}*\sqrt{11023}=6\sqrt{11023}$$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-630)-6\sqrt{11023}}{2*6}=\frac{630-6\sqrt{11023}}{12} $$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-630)+6\sqrt{11023}}{2*6}=\frac{630+6\sqrt{11023}}{12} $
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