B+5-5=2(b-3)-2(b-3)

Solution for B+5-5=2(b-3)-2(b-3) equation:

Simplifying
B + 5 + -5 = 2(b + -3) + -2(b + -3)

Reorder the terms:
5 + -5 + B = 2(b + -3) + -2(b + -3)

Combine like terms: 5 + -5 = 0
0 + B = 2(b + -3) + -2(b + -3)
B = 2(b + -3) + -2(b + -3)

Reorder the terms:
B = 2(-3 + b) + -2(b + -3)
B = (-3 * 2 + b * 2) + -2(b + -3)
B = (-6 + 2b) + -2(b + -3)

Reorder the terms:
B = -6 + 2b + -2(-3 + b)
B = -6 + 2b + (-3 * -2 + b * -2)
B = -6 + 2b + (6 + -2b)

Reorder the terms:
B = -6 + 6 + 2b + -2b

Combine like terms: -6 + 6 = 0
B = 0 + 2b + -2b
B = 2b + -2b

Combine like terms: 2b + -2b = 0
B = 0

Solving
B = 0

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Simplifying
B = 0