B+6/b-3=2

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Solution for B+6/b-3=2 equation: 



+6/B-3=2

We move all terms to the left:

+6/B-3-(2)=0



Domain of the equation: B!=0

B∈R



We add all the numbers together, and all the variables

6/B-5=0

We multiply all the terms by the denominator


-5*B+6=0

We add all the numbers together, and all the variables

-5B+6=0

We move all terms containing B to the left, all other terms to the right

-5B=-6

B=-6/-5

B=1+1/5

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