B+7=2/3b+17

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Solution for B+7=2/3b+17 equation: 



+7=2/3B+17

We move all terms to the left:

+7-(2/3B+17)=0



Domain of the equation: 3B+17)!=0

B∈R



We get rid of parentheses

-2/3B-17+7=0

We multiply all the terms by the denominator


-17*3B+7*3B-2=0

Wy multiply elements

-51B+21B-2=0

We add all the numbers together, and all the variables

-30B-2=0

We move all terms containing B to the left, all other terms to the right

-30B=2

B=2/-30

B=-1/15

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