B-17=3(2b-4)

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Solution for B-17=3(2b-4) equation: 



-17=3(2B-4)

We move all terms to the left:

-17-(3(2B-4))=0



We calculate terms in parentheses: -(3(2B-4)), so:

3(2B-4)

We multiply parentheses

6B-12

Back to the equation:

-(6B-12)



We get rid of parentheses

-6B+12-17=0

We add all the numbers together, and all the variables

-6B-5=0

We move all terms containing B to the left, all other terms to the right

-6B=5

B=5/-6

B=-5/6

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