B-2(5x+1)=6(33-10x)

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Solution for B-2(5x+1)=6(33-10x) equation: 



-2(5B+1)=6(33-10B)

We move all terms to the left:

-2(5B+1)-(6(33-10B))=0

We add all the numbers together, and all the variables

-2(5B+1)-(6(-10B+33))=0

We multiply parentheses

-10B-(6(-10B+33))-2=0



We calculate terms in parentheses: -(6(-10B+33)), so:

6(-10B+33)

We multiply parentheses

-60B+198

Back to the equation:

-(-60B+198)



We get rid of parentheses

-10B+60B-198-2=0

We add all the numbers together, and all the variables

50B-200=0

We move all terms containing B to the left, all other terms to the right

50B=200

B=200/50

B=4

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