B-3(x-5)=5-2(x+2)

Solution for B-3(x-5)=5-2(x+2) equation:

-3(B-5)=5-2(B+2)

We move all terms to the left:

-3(B-5)-(5-2(B+2))=0

We multiply parentheses

-3B-(5-2(B+2))+15=0


We calculate terms in parentheses: -(5-2(B+2)), so:

5-2(B+2)

determiningTheFunctionDomain
-2(B+2)+5

We multiply parentheses

-2B-4+5

We add all the numbers together, and all the variables

-2B+1

Back to the equation:

-(-2B+1)


We get rid of parentheses

-3B+2B-1+15=0

We add all the numbers together, and all the variables

-1B+14=0

We move all terms containing B to the left, all other terms to the right

-B=-14

B=-14/-1

B=+14