B.5(x+2)=4x+12

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Solution for B.5(x+2)=4x+12 equation: 



.5(B+2)=4B+12

We move all terms to the left:

.5(B+2)-(4B+12)=0

We multiply parentheses

0.5B-(4B+12)+1=0

We get rid of parentheses

0.5B-4B-12+1=0

We add all the numbers together, and all the variables

-3.5B-11=0

We move all terms containing B to the left, all other terms to the right

-3.5B=11

B=11/-3.5

B=-3+0.5/3.5

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