B/3b+4=16

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Solution for B/3b+4=16 equation: 



/3B+4=16

We move all terms to the left:

/3B+4-(16)=0



Domain of the equation: 3B!=0

B!=0/3

B!=0

B∈R



We add all the numbers together, and all the variables

/3B-12=0

We multiply all the terms by the denominator


-12*3B+=0

We add all the numbers together, and all the variables

-12*3B=0

Wy multiply elements

-36B=0

B=0/-36

B=0

Równanie nie ma rozwiązania

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