B/3b+5=8-4b

Solution for B/3b+5=8-4b equation:

/3B+5=8-4B

We move all terms to the left:

/3B+5-(8-4B)=0


Domain of the equation: 3B!=0

B!=0/3

B!=0

B∈R


We add all the numbers together, and all the variables

/3B-(-4B+8)+5=0

We get rid of parentheses

/3B+4B-8+5=0

We multiply all the terms by the denominator


4B*3B-8*3B+5*3B+=0

We add all the numbers together, and all the variables

4B*3B-8*3B+5*3B=0

Wy multiply elements

12B^2-24B+15B=0

We add all the numbers together, and all the variables

12B^2-9B=0

a = 12; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·12·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*12}=\frac{0}{24}
=0
$
$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*12}=\frac{18}{24}
=3/4
$