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/B+4=B+2
We move all terms to the left:
/B+4-(B+2)=0
Domain of the equation: B!=0We get rid of parentheses
B∈R
/B-B-2+4=0
We multiply all the terms by the denominator
-B*B-2*B+4*B+=0
We add all the numbers together, and all the variables
2B-B*B=0
Wy multiply elements
-1B^2+2B=0
a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$B_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2} =+2 $$B_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2} =0 $
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