B3(6y-1)=7(2y+3)

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Solution for B3(6y-1)=7(2y+3) equation: 



3(6B-1)=7(2B+3)

We move all terms to the left:

3(6B-1)-(7(2B+3))=0

We multiply parentheses

18B-(7(2B+3))-3=0



We calculate terms in parentheses: -(7(2B+3)), so:

7(2B+3)

We multiply parentheses

14B+21

Back to the equation:

-(14B+21)



We get rid of parentheses

18B-14B-21-3=0

We add all the numbers together, and all the variables

4B-24=0

We move all terms containing B to the left, all other terms to the right

4B=24

B=24/4

B=6

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