B=(1x+2)

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Solution for B=(1x+2) equation: 



=(1B+2)

We move all terms to the left:

-((1B+2))=0

We add all the numbers together, and all the variables

-((B+2))=0



We calculate terms in parentheses: -((B+2)), so:

(B+2)

We get rid of parentheses

B+2

Back to the equation:

-(B+2)



We get rid of parentheses

-B-2=0

We add all the numbers together, and all the variables

-1B-2=0

We move all terms containing B to the left, all other terms to the right

-B=2

B=2/-1

B=-2

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