B=(35-a)/3

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Solution for B=(35-a)/3 equation: 


x in (-oo:+oo)

B = (35-a)/3 // - (35-a)/3

B-((35-a)/3) = 0

(-1*(35-a))/3+B = 0

(-1*(35-a))/3+(3*B)/3 = 0

3*B-1*(35-a) = 0

3*B+a-35 = 0

(3*B+a-35)/3 = 0

(3*B+a-35)/3 = 0 // * 3

3*B+a-35 = 0

x belongs to the empty set

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