B=03x2=21=0

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Solution for B=03x2=21=0 equation: 



=03B^2=21=0

We move all terms to the left:

-(03B^2)=0

We add all the numbers together, and all the variables

-3B^2=0

a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$B=\frac{-b}{2a}=\frac{0}{-6}=0$

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