B=2+2+(n-1)

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Solution for B=2+2+(n-1) equation: 



=2+2+(B-1)

We move all terms to the left:

-(2+2+(B-1))=0



We calculate terms in parentheses: -(2+2+(B-1)), so:

2+2+(B-1)

determiningTheFunctionDomain
(B-1)+2+2

We add all the numbers together, and all the variables

(B-1)+4

We get rid of parentheses

B-1+4

We add all the numbers together, and all the variables

B+3

Back to the equation:

-(B+3)



We get rid of parentheses

-B-3=0

We add all the numbers together, and all the variables

-1B-3=0

We move all terms containing B to the left, all other terms to the right

-B=3

B=3/-1

B=-3

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