B=2-(2b-4)/3

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Solution for B=2-(2b-4)/3 equation: 


x in (-oo:+oo)

B = 2-((2*b-4)/3) // - 2-((2*b-4)/3)

(2*b-4)/3+B-2 = 0

(2*b-4)/3+(3*B)/3+(-2*3)/3 = 0

3*B+2*b-2*3-4 = 0

3*B+2*b-6-4 = 0

3*B+2*b-10 = 0

(3*B+2*b-10)/3 = 0

(3*B+2*b-10)/3 = 0 // * 3

3*B+2*b-10 = 0

x belongs to the empty set

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