B=3/2(j-69)

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Solution for B=3/2(j-69) equation:



=3/2(B-69)
We move all terms to the left:
-(3/2(B-69))=0
Domain of the equation: 2(B-69))!=0
B∈R
We multiply all the terms by the denominator
-(3=0
We add all the numbers together, and all the variables
=0
B=0/1
B=0

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