B=3/4a+11

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Solution for B=3/4a+11 equation: 



=3/4B+11

We move all terms to the left:

-(3/4B+11)=0



Domain of the equation: 4B+11)!=0

B∈R



We get rid of parentheses

-3/4B-11=0

We multiply all the terms by the denominator


-11*4B-3=0

Wy multiply elements

-44B-3=0

We move all terms containing B to the left, all other terms to the right

-44B=3

B=3/-44

B=-3/44

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