B=4/3(j-98)

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Solution for B=4/3(j-98) equation: 


x in (-oo:+oo)

B = (4/3)*(j-98) // - (4/3)*(j-98)

B-((4/3)*(j-98)) = 0

(-4/3)*(j-98)+B = 0

B-4/3*(j-98) = 0

B-4/3*(j-98) = 0

B-4/3*j+392/3 = 0

B-4/3*j+392/3 = 0

x belongs to the empty set

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