B=5/2(j-39)

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Solution for B=5/2(j-39) equation: 


x in (-oo:+oo)

B = (5/2)*(j-39) // - (5/2)*(j-39)

B-((5/2)*(j-39)) = 0

(-5/2)*(j-39)+B = 0

B-5/2*(j-39) = 0

B-5/2*(j-39) = 0

B-5/2*j+195/2 = 0

B-5/2*j+195/2 = 0

x belongs to the empty set

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