B=6/5(j-23)

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Solution for B=6/5(j-23) equation: 


x in (-oo:+oo)

B = (6/5)*(j-23) // - (6/5)*(j-23)

B-((6/5)*(j-23)) = 0

(-6/5)*(j-23)+B = 0

B-6/5*(j-23) = 0

B-6/5*(j-23) = 0

B-6/5*j+138/5 = 0

B-6/5*j+138/5 = 0

x belongs to the empty set

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