B=7/3(j-80)

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Solution for B=7/3(j-80) equation: 



=7/3(B-80)

We move all terms to the left:

-(7/3(B-80))=0



Domain of the equation: 3(B-80))!=0

B∈R



We multiply all the terms by the denominator


-(7=0

We add all the numbers together, and all the variables

=0

B=0/1

B=0

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